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queue runner: attempt at slightly smarter scheduling criteria

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Instead of just going for "whatever is the oldest build we know of",
use the following first:

- Is the step more constrained? If so, schedule it first to avoid
  filling up "more desirable" build slots with less constrained builds.

- Does the step have more dependents? If so, schedule it first to try
  and maximize open parallelism and breadth of scheduling options.

(cherry picked from commit b8d03adaf4)
This commit is contained in:
Pierre Bourdon 2024-04-21 17:36:16 +02:00 committed by ahuston-0
parent 21f793e21b
commit 0dd4c0cc8e
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1 changed files with 6 additions and 0 deletions
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6
src/hydra-queue-runner/dispatcher.cc
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@ -134,6 +134,8 @@ system_time State::doDispatch()
comparator is a partial ordering (see MachineInfo). */
int highestGlobalPriority;
int highestLocalPriority;
size_t numRequiredSystemFeatures;
size_t numRevDeps;
BuildID lowestBuildID;
StepInfo(Step::ptr step, Step::State & step_) : step(step)
@ -142,6 +144,8 @@ system_time State::doDispatch()
lowestShareUsed = std::min(lowestShareUsed, jobset->shareUsed());
highestGlobalPriority = step_.highestGlobalPriority;
highestLocalPriority = step_.highestLocalPriority;
numRequiredSystemFeatures = step->requiredSystemFeatures.size();
numRevDeps = step_.rdeps.size();
lowestBuildID = step_.lowestBuildID;
}
};
@ -194,6 +198,8 @@ system_time State::doDispatch()
a.highestGlobalPriority != b.highestGlobalPriority ? a.highestGlobalPriority > b.highestGlobalPriority :
a.lowestShareUsed != b.lowestShareUsed ? a.lowestShareUsed < b.lowestShareUsed :
a.highestLocalPriority != b.highestLocalPriority ? a.highestLocalPriority > b.highestLocalPriority :
a.numRequiredSystemFeatures != b.numRequiredSystemFeatures ? a.numRequiredSystemFeatures > b.numRequiredSystemFeatures :
a.numRevDeps != b.numRevDeps ? a.numRevDeps > b.numRevDeps :
a.lowestBuildID < b.lowestBuildID;
});