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Merge the BuildSchedulingInfo table into the Builds table

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This simplifies the code and improves performance since it reduces
the number of joins.
This commit is contained in:
Eelco Dolstra
2012-02-29 02:22:49 +01:00
parent 19fe4b9b4a
commit 25334715f8
21 changed files with 194 additions and 301 deletions
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12
src/lib/Hydra/Helper/Nix.pm
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@ -195,13 +195,13 @@ sub jobsetOverview {
return $project->jobsets->search( isProjectOwner($c, $project) ? {} : { hidden => 0 },
{ order_by => "name"
, "+select" =>
[ "(SELECT COUNT(*) FROM Builds AS a NATURAL JOIN BuildSchedulingInfo WHERE me.project = a.project AND me.name = a.jobset AND a.isCurrent = 1)"
, "(SELECT COUNT(*) FROM Builds AS a NATURAL JOIN BuildResultInfo WHERE me.project = a.project AND me.name = a.jobset AND buildstatus <> 0 AND a.isCurrent = 1)"
, "(SELECT COUNT(*) FROM Builds AS a NATURAL JOIN BuildResultInfo WHERE me.project = a.project AND me.name = a.jobset AND buildstatus = 0 AND a.isCurrent = 1)"
, "(SELECT COUNT(*) FROM Builds AS a WHERE me.project = a.project AND me.name = a.jobset AND a.isCurrent = 1)"
[ "(select count(*) from Builds as a where a.finished = 0 and me.project = a.project and me.name = a.jobset and a.isCurrent = 1)"
, "(select count(*) from Builds as a join BuildResultInfo r using (id) where me.project = a.project and me.name = a.jobset and buildstatus <> 0 and a.isCurrent = 1)"
, "(select count(*) from Builds as a join BuildResultInfo r using (id) where me.project = a.project and me.name = a.jobset and buildstatus = 0 and a.isCurrent = 1)"
, "(select count(*) from Builds as a where me.project = a.project and me.name = a.jobset and a.isCurrent = 1)"
]
, "+as" => ["nrscheduled", "nrfailed", "nrsucceeded", "nrtotal"]
});
, "+as" => ["nrscheduled", "nrfailed", "nrsucceeded", "nrtotal"]
});
}
sub getViewResult {